EF=(1.054×10-34)22(9.11×10-31)(3π2×8.45×1028)2/3cap E sub cap F equals the fraction with numerator open paren 1.054 cross 10 to the negative 34 power close paren squared and denominator 2 open paren 9.11 cross 10 to the negative 31 power close paren end-fraction open paren 3 pi squared cross 8.45 cross 10 to the 28th power close paren raised to the 2 / 3 power Calculate the intermediate terms:
(2.502×1030)2/3≈1.842×1020open paren 2.502 cross 10 to the 30th power close paren raised to the 2 / 3 power is approximately equal to 1.842 cross 10 to the 20th power solid state physics by puri and babbar solutions pdf new
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